## How to Sing Valerie Amy Winehouse Cover Tori Matthieu Ken Tamplin Vocal Academy

Hey guys welcome back again to Ken TamplinVocal Academy, where the proof is in the singing. I'm here with my amazing student, Tori Matthieu,and we're doing takedowns of different songs today. We're going to do Amy Winehouse.The song's called Valerie. We'll do it first. We'll talk about it after, likewe always do. Let's rock! Amy Winehouse. Whooh! Nice job, girl! Man, that was good.Thank you. All right, so basically, we're doing a lotof different stuff, from Alicia Keys, Stevie Wonder, Amy Winehouseâ€¦ And what's interestingabout this is not so much that we're just doing a bunch of cover songs, but it's howTori finds herself in the song, and actually

represents that art with her own touch, herown flair, but to be able to sing in a lot of different styles, because what this doesis to give you a lot of tools for your toolbox for singing. So, we're going to be working upon, actually, some original material, too, so be watching out for that. Anyway, this is KenTamplin Vocal Academy. If you like what you see here, please like and subscribe to mytutorials. Also, I have a killer course, you can check it out here. It's called â€œHowTo Sing Better Than Anyone Elseâ€� and I have a singer's forums. It's free. There areover 6000 members you can join at Ken Tamplin Vocal Academy, and just come by and say hi,and get your vocal questions answered. So,

until next time, Tori Matthieu, Amy Winehouse,Valerie, and Rock!.

## Can You Pass A 5th Grade Spelling Test

(electronic music) Aw fuck! (laughing) Is that everybody else'sreaction to Mediterraneané Mediterranean Okay. M E DIT All right now this iswhere it gets tricky.

ERR E A I NEAN, Mediterranean (bell sound)Yeah! (buzzer sound) Dammit! (bell sound) (bell sound) Yeah! (bell sound) Woo! Fire.

(bell sound) Of course it is! (buzzer sound) Are you sureé Privilege PR I V E E E I L E

D GE Privilege (buzzer sound)Fuck! (buzzer sound) Dammit! (bell sound) Yes! (buzzer sound) Aww, what did I doé (buzzer sound) Whaté (buzzer sound) Yeah. (bell sound) Killin' it.

Definitelyé Oh I definitelyknow how to spell this. Definitely know how to spell definitely. Now this one, I definitely know. D E F Just quot;defquot;, no. (laughs) I N E IT ELY, definitely.(bell sound)

(bell sound) Yes! (bell sound) Yeah. (bell sound) Yay. (bell sound) (bell sound) Yes! (buzzer sound) Yeah. Woo! Diarrhea, cha cha cha.

### Trigonometry Lessons Part 1 Definitions

The trig functions are ratios of the sides of a right triangle, so we have to name the sides. Let's call the angle theta. We all know that the longest side is called the hypotenuse. The side opposite theta is called its opposite side, and the third side is called its adjacent side. If we know two sides of a right triangle, the Pythagorean theorem gives us the other side.

The hypotenuse squared is the sum of the squares of the other two sides. These other formats simplify our work. The easiest way is to keep in mind that the hypotenuse is the longest side. So to find the hypotenuse we add, whereas to find the shorter sides we subtract from the hypotenuse. Now we can define the trig functions. To begin, we need only two the sine and cosine. The sine of an angle is defined to be its opposite side divided by the hypotenuse.

Suppose you use the large triangle, and your friend uses the tiny one. Do you get the same value for sine thetaé Yes, because the triangles are similar. So we don't have to worry about that. The cosine of an angle is defined to be its adjacent side divided by the hypotenuse. We'll use two important triangles as examples. First, the 30, 60, 90 degree one. Let's figure out the sides of such a triangle.

A clever way is to cut an equilateral triangle in half with a perpendicular bisector. To avoid fractions, let's choose 1 and 2 as the lengths of the sides. How do we find the other sideé Of course, by the Pythagorean Theorem. The square root of 2 squared minus 1 squared, is the square root of 3. Now we are ready to find the sine and cosine of some angles. Let's find sine of 30 degrees. Sine is opposite over hypotenuse. The opposite side of 30 degrees is 1. The hypotenuse is 2, so sine of 30 degrees equals 12.

Let's find the sine of 60 degrees next. Same thing. Opposite over hypotenuse. Look at the angle 60 degrees. Its opposite side has length square root 3. So the sine of 60 degrees equals square root of 3 over 2. Oké On to the cosines. Cosine is adjacent over hypotenuse. The adjacent side of the 30 deg angle is sq root 3. The hypotenuse is 2. That means cosine of 30 deg equals to square root of 3 over 2. The adjacent side of the 60 deg angle is 1.

The hypotenuse is 2. That means cosine of 60 deg equals to 1 over 2. Here's a summary of our results. Let's look at another important right triangle, an isosceles right triangle. For the equal sides, the simplest numbers to use would be 1 and 1. The two acute angles are 45 degrees. Let's find the hypotenuse. Square root of 1 squared plus 1 squared. Easy, square root 2. This triangle is complete, now we can calculate the sine and cosine of 45 degrees.